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Submitted by xman on Tue, 19/09/2006 - 9:39pm
Posted in
Solving:
$ax^2 + bx + c = 0$
Then
$x = \frac{-b + \sqrt{b^2 - 4ac}}{2a}$
or
$x = \frac{-b - \sqrt{b^2 - 4ac}}{2a}$
Solving:
$ax^2 + bx + c = 0$
Then
$x = \frac{-b + \sqrt{b^2 - 4ac}}{2a}$
or
$x = \frac{-b - \sqrt{b^2 - 4ac}}{2a}$
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