Sponsors
Submitted by xman on Tue, 19/09/2006 - 9:39pm
Posted in
Solving:
$ax^2 + bx + c = 0$
Then
$x = \frac{-b + \sqrt{b^2 - 4ac}}{2a}$
or
$x = \frac{-b - \sqrt{b^2 - 4ac}}{2a}$
Solving:
$ax^2 + bx + c = 0$
Then
$x = \frac{-b + \sqrt{b^2 - 4ac}}{2a}$
or
$x = \frac{-b - \sqrt{b^2 - 4ac}}{2a}$
Recent comments
3 weeks 1 day ago
11 weeks 2 days ago
13 weeks 5 days ago
20 weeks 15 hours ago
30 weeks 4 days ago
30 weeks 5 days ago
31 weeks 6 days ago
42 weeks 6 days ago
43 weeks 4 hours ago
1 year 18 weeks ago